
An Armstrong number of three digits is an integer such that the sum of the cubes of its digits is equal to the number itself. For example, 371 is an Armstrong number since 3**3 + 7**3 + 1**3 = 371.
Step 1: Start
Step 2: Read n
Step 3: Rem=n
Step 4: sum=0
Step 5: If n != 0,
rem=n%0
sum=sum+(rem*rem*rem)
Step 6: n=n/10, goto 5
Step 7: If n=0, then if temp=arm, print Number is armstrong
Step 8: if temp is not equal to arm print Number is not armstrong
Step 9: Stop
Step 2: Read n
Step 3: Rem=n
Step 4: sum=0
Step 5: If n != 0,
rem=n%0
sum=sum+(rem*rem*rem)
Step 6: n=n/10, goto 5
Step 7: If n=0, then if temp=arm, print Number is armstrong
Step 8: if temp is not equal to arm print Number is not armstrong
Step 9: Stop
Program :
#include int main() { int number, sum = 0, n, rem; printf("Enter a number\n"); scanf("%d",&number); n = number; while( n != 0 ) { rem = n%10; sum = sum + rem*rem*rem; n = n/10; } if ( number == sum ) printf("Entered number is an armstrong number."); else printf("Entered number is not an armstrong number."); return 0; }